192=x^2+16x

Solution for 192=x^2+16x equation:

192=x^2+16x

We move all terms to the left:

192-(x^2+16x)=0

We get rid of parentheses

-x^2-16x+192=0

We add all the numbers together, and all the variables

-1x^2-16x+192=0

a = -1; b = -16; c = +192;
Δ = b2-4ac
Δ = -162-4·(-1)·192
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*-1}=\frac{48}{-2}
=-24
$